The current in a wire varies with time according to the equation I=4+2t, where I is in ampere and t is in second. The quantity of charge which has to be passed through a cross-section of the wire during the time t=2s to t=6s is?
A
40C
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B
48C
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C
38C
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D
43C
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Solution
The correct option is D48C
Given:
I=4+2t
Let dq be the charge which passes in a small interval of time dt. Then
dq=Idt or dq=(4+2t)dt On integrating, we get q=∫62(4+2t)dt=[4t+t2]62=48C