MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

More about Magnetic Dipoles

The current i...

Question

The current (in Ampere) in an inductor is given by $I = 5 + 16 t$ , where $t$ is in seconds. The self-induced emf in it is $10 m V$ . Find the self-inductance.

Open in App

Solution

$\frac{d I}{d t} = 16 A / s$

$∴ L = ∣ ∣ ∣ ∣ ∣ \frac{e}{\frac{d I}{d t}} ∣ ∣ ∣ ∣ ∣ = \frac{10 \times 10^{- 3}}{16} = 0.625 \times 10^{- 3} H$

$= 0.625 m H$

Suggest Corrections

thumbs-up

0

Similar questions

Q. The current (in Ampere) in an inductor is given by

I = 5 + 16 t

t

is in seconds. The self-induced emf in it is

10 m V

. Find the energy stored in the inductor and the power supplied to it at

t = 1 s

Q. A solenoid has self inductance of

5 mH

and the current through it is given by

i = 5 t^{2}

t

is time in second. The induced emf at

t = 1 s

Q. A solenoid has self inductance of

5 mH

and the current through it is given by

i = 10 t^{2} - 20 t

t

is time in second. At what instant of time, the induced emf will be zero?

Q. An average emf of 20 V is induced in an inductor when the current in it is changed from 2.5 A in one direction to the same value in the opposite direction in 0.1 s. Find the self-inductance of the inductor.

Q. When current changes from

4 A

0 A

0.1 s

in an inductor the induced emf is found to be

100 V

, then find the value of self-inductance is :

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Torque on a Magnetic Dipole

PHYSICS

Watch in App

explore_more_icon

Explore more

More about Magnetic Dipoles

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon