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The current i...

Question

The current (in Ampere) in an inductor is given by $I = 5 + 16 t$ , where $t$ is in seconds. The self-induced emf in it is $10 m V$ . Find the self-inductance.

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Solution

$\frac{d I}{d t} = 16 A / s$

$∴ L = ∣ ∣ ∣ ∣ ∣ \frac{e}{\frac{d I}{d t}} ∣ ∣ ∣ ∣ ∣ = \frac{10 \times 10^{- 3}}{16} = 0.625 \times 10^{- 3} H$

$= 0.625 m H$

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