Question

The current in branch $CD$ of given circuit is then :

• A. 0
  
• B. 1
• C. 2
• D. 3

Answer 1

The correct option is A 0

$ApplyingKirchofflaw,inACBD,2i+4i_1=-4+12=>2i+4i_1=8=>i+2i_1=4-------\left(1\right)ApplyingKirchofflawinloopCDFE,=>-4i_1+3(i-i_1)=4+8=>-4i+3i-3i_1=12=>3i-7i_1=12---------\left(2\right)From\left(1\right)and\left(2\right)=>3(4-2i_1)-7i_1=12=>12-6i_1-7i_1=12=>-13i_1=0=>i_1=0HencecurrentinbranchCDiszero$