Question

The current in the given circuit is increasing with a rate $a=4$ amp/s. The charge on the capacitor at an instant when the current in the circuit is $2$ amp will be:

• A. $4\mu C$
• B. $5\mu C$
• C. $6\mu C$
• D. None of these

Answer 1

The correct option is C $6\mu C$

Given $\frac{dI}{dt}=4A/S$ when convesrt $I=2A$

we KVL acron loop :-

$E-IR-L\frac{dI}{dt}-\frac{9}{c}=0$ (sum of are voltangers across a loop In zero)

put value,

$\Rightarrow 4-2\times 1-1\times 4-\frac{9}{3}=0\Rightarrow 9=6\mu C$ (Ans)