Question

The current in the given circuit is increasing with a rate $a=4\text{amp/s}$. The charge on the capacitor at an instant when the current in the circuit is $2\text{amp}$ will be :

• A. $4\mu C$
• B. $5\mu C$
• C. $6\mu C$
• D. None of these

Answer 1

The correct option is C $6\mu C$


Writing KVL along the closed loop.
$4-2-\frac{Ldi}{dt}-\frac{q}{C}=0$,
$2-4-\frac{q}{C}=0$
$q=-6\mu C$
So, the charge on capacitor is $6\mu C$