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Byju's Answer
Standard XII
Physics
Power in an AC Circuit
The current i...
Question
The current is given as
x
10
A
. Find
x
Open in App
Solution
Z
1
=
115
3
=
38.33
Ω
cos
ϕ
1
=
R
1
Z
1
⇒
R
1
=
Z
1
cos
ϕ
1
=
(
38.33
)
(
0.6
)
=
23
Ω
X
L
=
√
Z
2
1
−
R
2
1
=
30.67
Ω
Z
2
=
115
5
=
23
Ω
R
2
=
Z
2
cos
ϕ
2
=
(
23
)
(
0.707
)
=
16.26
Ω
When connected in series
R
=
R
1
+
R
2
=
39.26
Ω
X
L
−
X
C
=
14.41
Ω
∴
Z
=
√
R
2
+
(
X
L
−
X
C
)
2
=
41.82
Ω
i
=
V
Z
=
230
41.82
=
5.5
A
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0
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