The current passing through a choke coil of $5 H$ is decreasing at the rate of $2 A / s$ . The e.m.f. developed across the coil is

10 V

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- 10 V

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2.5 V

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- 2.5 V

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Solution

The correct option is A $10 V$
$L = 5 H, \frac{d I}{d t} = - 2 A s^{- 1}$
$e = - L \frac{d I}{d t} = 5 \times 2 = 10 V$

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The current passing through a choke coil of 5H is decreasing at the rate of 2A/s. The e.m.f. developed across the coil is

The correct option is A 10VL=5H,dIdt=−2As−1e=−LdIdt=5×2=10V

The current passing through a choke coil of $5 H$ is decreasing at the rate of $2 A / s$ . The e.m.f. developed across the coil is

The correct option is A $10 V$
$L = 5 H, \frac{d I}{d t} = - 2 A s^{- 1}$
$e = - L \frac{d I}{d t} = 5 \times 2 = 10 V$