The current passing through a wire is 5A. If the resistance of the wire is 4Ώ, then what is the work done to move a charge of 4C across the wire if the potential difference is kept constant?

5 J

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20 J

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40 J

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80 J

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Solution

The correct option is D
80 J

Given, $I = 5 A$ and $R = 4 Ω$
If $V$ is the potential difference across the ends of the wire:
$V = I R$ (Ohm's Law)

$V$ = $5 \times 4$

Or, $V$ = $20 V$

Now, charge ( $q$ ) is equal to 4 $C$

Hence, work done ( $W$ ) is given by
$W$ = $q \times V$
$W$ = $4 \times 20$
Or, $W$ = $80 J$

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The current passing through a wire is 5A. If the resistance of the wire is 4Ώ, then what is the work done to move a charge of 4C across the wire if the potential difference is kept constant?

The correct option is D 80 J Given, I=5 A and R=4 Ω If V is the potential difference across the ends of the wire: V=IR (Ohm's Law) V = 5×4 Or, V = 20 V Now, charge (q) is equal to 4 C Hence, work done (W) is given by W = q×V W = 4×20 Or, W = 80 J