The current passing through an electric kettle has been doubled. The heat produced will become: (a) half (b) double (c) four times (d) one - fourth
H=I2Rt now I = 2 so H=(2)2Rt
H=4Rt so heat produced will become,
(c) four times
If the potential difference between the ends of a fixed resistor is halved the electric power will become.
(A) Four times
(B) One-Fourth
(C) Double
(D) Half
Keeping the p.d. constant, the resistance of the circuit is halved. The current will become. (a) One-fourth (b) four times (c) half (d) double