The current passing through an electric kettle has been doubled. The heat produced will become:
(a) half (b) double (c) four times (d) one - fourth

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Solution

$H = I^{2} R t$
now I = 2
so $H = (2)^{2} R t$

$H = 4 R t$
so heat produced will become,

(c) four times

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