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Byju's Answer
Standard XII
Physics
Galvanometer
The current s...
Question
The current sensitivity of a moving coil galvanometer depends on
A
the number of turns in the coil
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B
moment of inertia of the coil
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C
current sent through galvanometer
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D
eddy current in A1 frame
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Solution
The correct option is
A
the number of turns in the coil
Current sensitivity
=
n
B
A
K
where K is constant of torsional rigidity.
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Similar questions
Q.
A moving-coil galvanometer has its coil of
24
turns and
12
Ω
resistance. By how much the number of turns should be increased so that the current sensitivity of the galvanometer increases by
25
%? If, in doing so, the resistance of the coil increases to
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, what will be the effect on the voltage-sensitivity of the galvanometer?
Q.
Obtain the expression for current sensitivity of moving coil galvanometer.
Q.
In the moving coil galvanometer
N= number of turns; A= cross sectional area; B= Magnetic field; C= Torsional constant; I= current, R= resistance
List I
List II
(P)
Torque action on the coil
(1)
NAB /C
(Q)
Deflection produced
(2)
NAB/CR
(R)
Current sensitivity
(3)
NIAB
(S)
Voltage sensitivity
(4)
NABI/C
Q.
The relation between voltage sensitivity
(
σ
v
)
and current sensitivity
(
σ
1
)
of a moving coil galvanometer is (resistance of galvanometer is G).
Q.
A moving coil galvanometer has 48 turns and area of coil is
4
×
10
−
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m
2
. If the magnetic field is 0.2T, then to increase the current sensitivity by 25% without changing area (A) and field (B) the number of turns should become :
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