Question

The current supplied by the battery in the circuit shown in figure is

• A. $2\text{A}$
• B. $1\text{A}$
• C. $3\text{A}$
• D. $1.5\text{A}$

Answer 1

The correct option is B $1\text{A}$

The circuit can be reduced by applying the successive reduction for parallel and series combination of resistances.

For parallel combination we can use,

$R_{\text{eq}}=\frac{R_1{R}_2}{R_1+R_2}$

Redrawing the circuit after simplification,


Therefore the equivalent resistance of circuit across the terminals of battery is,

$R_{\text{eq}}=8+0.5+2+4.5=15\Omega$

The current supplied from the battery will be,

$i=\frac{V}{R_{\text{eq}}}=\frac{15}{15}=1\text{A}$