Question

The current through $10\Omega$ resistor shown in figure is

• A. Zero
• B. $1\text{A}$
• C. $1.5\text{A}$
• D. $2\text{A}$

Answer 1

The correct option is A Zero

In the given circuit, two cells with opposite polarity are connected in parallel. So net emf of given circuit will be

$E_{net}=\frac{\frac{E_1}{r_1}-\frac{E_2}{r_2}}{\frac{1}{r_1}+\frac{1}{r_2}}$

$\Rightarrow E_{net}=\frac{\frac{5}{1}-\frac{10}{2}}{\frac{1}{1}+\frac{1}{2}}=\frac{5-5}{1+0.5}$

$\therefore E_{net}=0$

Since the net emf is zero in the circuit, so zero current will flow through the circuit and resistor $10\Omega$.

Therefore, option $\left(a\right)$ is correct.