The current through a 20- resistor connected to a 12V battery is-

The correct option is E 0.6 #160;amperes Ohm's law states , #160; V=IR given R=20Ω #160;, #160; V=12V #160;therefore , #160; ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Physics

Ohm's Law

The current t...

Question

The current through a $20 Ω$ resistor connected to a $12 V$ battery is:

0.3 a m p e r e s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.6 a m p e r e s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.9 a m p e r e s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.6 a m p e r e s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.9 a m p e r e s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is E $0.6 a m p e r e s$
Ohm's law states , $V = I R$
given - $R = 20 Ω, V = 12 V$
therefore , $12 = I \times 20$
or $I = 12 / 20 = 0.6 A$

Suggest Corrections

Similar questions

Q. When a resistor is connected to a 12 V battery, a current of 0.4 A flows through it. Find its resistance.

Resistors $R_{1}$ =10 $Ω$ , $R_{2}$ = 40 $Ω$ , $R_{3}$ = 30 $Ω$ , $R_{4}$ = 20 $Ω$ , $R_{5}$ = 60 $Ω$ and a 12V battery is connected as shown.

Calculate:
(a) the total resistance
(b) the total current flowing in the circuit.

Three resistors are connected to a 12 V battery as shown in the figure given below:

The current through the 8 ohm resistor is:

Q. Two resistors of resistances

10 Ω

and

20 Ω

are connected in parallel. A battery supplies

6 A

of current to the combination. Calculate the current in each resistor.

When a 12 V battery is connected across an unknown resistor, there is a current of 2.5 mA in the circuit. Find the value of the resistance of the resistor.

Join BYJU'S Learning Program

The current through a 20Ω resistor connected to a 12V battery is:

The correct option is E 0.6 amperesOhm's law states , V=IRgiven - R=20Ω,V=12V therefore , 12=I×20 or I=12/20=0.6A

The current through a $20 Ω$ resistor connected to a $12 V$ battery is:

The correct option is E $0.6 a m p e r e s$
Ohm's law states , $V = I R$
given - $R = 20 Ω, V = 12 V$
therefore , $12 = I \times 20$
or $I = 12 / 20 = 0.6 A$