Question

The current through a conductor is 1 ampere. The no. of electrons that pass through the conductor in one second is:

• A. $3.125\times {10}^{18}$
• B. $6\times {10}^{18}$
• C. $6.25\times {10}^{18}$
• D. $12.5\times {10}^{18}$

Answer 1

Answer: (C)

$6.25\times {10}^{18}$

We Know that,

Charge of electron $e=1.6\times {10}^{-19}$

Current $i=1A$

Now, the number of electrons that pass through the conductor in one second is

We know that,

$I=ne$

$1A=n\times 1.6\times {10}^{-19}C$

$n=\frac{1}{1.6\times {10}^{-19}}$

$n=6.25\times {10}^{18}$

Hence, the number of electrons is $6.25\times {10}^{18}$