The current through a resistor of 2 - is 1 A- What is the potential difference across it-A- 2 VB- 4 VC- 1 VD- 1-2 V

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Physics

Ohm's Law

The current t...

Question

The current through a resistor of $2 Ω$ is 1 A. What is the potential difference across it?

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{2 V}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 2V
Simply apply the relation,
V = iR
$V = 2 \times 1$
V = 2V

Suggest Corrections

Similar questions

Q. The current through a resistor of

2 Ω

is 1 A. What is the potential difference across it?

Q. In the circuit shown below:

Ώ

The potential difference across the 3 Ω resistor is:

(a)

\frac{1}{9}

V
(b)

\frac{1}{2}

V
(c) 1 V
(d) 2 V

In the given set up resistors A, B & C are of resistance 1 ohm each.

Find the current through resistor A and Potential difference across it

Two resistors 4 Ω and 2 Ω are connected in series, and potential difference of 12 V is applied across the combination. Then, the current through the circuit is:

Q. The given figure shows three resistors of

2 Ω

4 Ω

and

R Ω

connected to a battery of EMF 2V and internal resistance

3 Ω

.A main current of 0.25 A flows through the circuit.

(a) What is the potential difference across the

4 Ω

resistor?
(b) Calculate the potential difference across the internal resistance of the cell.
(c) What is the potential difference across the

R Ω

2 Ω

resistors?
(d) Calculate the value of R.
[5 MARKS]

Join BYJU'S Learning Program

The current through a resistor of 2Ω is 1 A. What is the potential difference across it?

The correct option is A 2VSimply apply the relation, V = iR V=2×1 V = 2V

The current through a resistor of $2 Ω$ is 1 A. What is the potential difference across it?

The correct option is A 2V
Simply apply the relation,
V = iR
$V = 2 \times 1$
V = 2V