The current through a wire depends on time as, $i = (10 + 4 t)$ Here, $i$ is in ampere and $t$ is in seconds. Find the charge that crosses through a section in time interval between $t = 0$ to $t = 1 s$ .

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Solution

Given:current=(10+4t)
charge= $\int i d t \int (10 + 4 t) d t = [10 t + \frac{4 t^{2}}{2}]_{0}^{1} = 10 + 2 = 12 c o u l o m b$

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The current through a wire depends on time as, i=(10+4t) Here, i is in ampere and t is in seconds. Find the charge that crosses through a section in time interval between t=0 to t=1s.

Given:current=(10+4t)charge=∫idt∫(10+4t)dt=[10t+4t22]10=10+2=12coulomb

The current through a wire depends on time as, $i = (10 + 4 t)$ Here, $i$ is in ampere and $t$ is in seconds. Find the charge that crosses through a section in time interval between $t = 0$ to $t = 1 s$ .

Given:current=(10+4t)
charge= $\int i d t \int (10 + 4 t) d t = [10 t + \frac{4 t^{2}}{2}]_{0}^{1} = 10 + 2 = 12 c o u l o m b$