The correct option is
C 0.6A
Using Kirchhoff's law for loop ABVHA
2−2I1−2I=0
⟹2=2(I1−I)
⟹I1=1−i→(1)
Using Kirchhoff's law for loop AHVGPBA
2I+2+2I2−2=0
⟹I=−I2→(2)
Using Kirchhoff's law for loop AHVGUCPBA
2I+2+2I3−2−2=0
I+I3=1
⟹I3=1−I→(3)
Using Kirchhoff's law for loop AHVGUFQCPBA
⟹2I+2+2+I4(2)−2−2=0
I4=−I→(4)
Using Kirchhoff's law for loop AHUGUFTDQCPBA
⟹2I+2+2+I5(2)−2−2−2=0
I5=−I→(5)
Using Kirchhoff's law for loop AHUGuFTERDQCPBA
⟹2I+2+2+2+2(I−I1−I2−I3−I4−I5)−2−2−2=0
I1+I2+I3+I4+I5=0→(6)
Using equations (1),(2),(3),(4),(5) in (6)
⟹1−I−I+1−I−I+1−I=0
⟹5I=3⟹I=35A
Current through arm AB⟹I=35=0.6A