The correct option is B Parabola
x=3cos(2t),y=1+cos2(2t)
cos2(2t)=(x3)2
cos2(2t)=x29⋯⋯(1)
cos2(2t)=y−1⋯⋯(2)
Equalising equation (1) and (2)
y−1=x29
x2−9y+9=0
On comparing with ax2+by2+2hxy+2gx+2fy+c=0
We have a=1,b=0,h=0,g=0,f=−92,c=9
Δ=0+0−814−0−0≠0
and h2=ab
Hence it represents a parabola .