The curve given by the equation $x^{2} + y^{2} = 3 a x y$ is

symmetrical about x-axis

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symmetrical about y-axis

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symmetrical about the line y = x

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tangential to x = y = a/3

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Solution

The correct option is C symmetrical about the line y = x
Replacing x by y and y by x equation of curve remains unaltered means f(y, x) = f(x,y). Hence, curve is symmetric about the line y = x

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Similar questions

\frac{d y}{d x} = \frac{x^{2} + y^{2}}{2 x y}

x^{2} - y^{2} = C X

x^{2} + y^{2} = 2 a y

(x, y)

(3, 0)

(3, 4)

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x^{2} - y^{2} + λ x y = a^{2}

(x^{2} + y^{2})^{2} = a^{2} (x^{2} - y^{2}) .

\frac{d y}{d x} = \frac{2 y}{x}; x > 0, y > 0

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