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Question

The curve given by x+y=exy has a tangent parallel to the y-axis at the point

A
(0,1)
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B
(1,0)
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C
(1,1)
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D
(1,1)
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Solution

The correct option is B (1,0)
Given curve is x+y=exy
On differentiating w.r.t x we get
1+dydx=exy{y+xdydx}
dydx=yexy11xexy
Since, tangent is parallel to y-axis
Here, dydx=1xexy=0
1x(x+y)=0
This holds for x=1,y=0

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