The curved surface area of a cone is 4070 $c m^{2}$ and its diameter is 70 cm.What is the slant height ?(Use $π = \frac{22}{7}$ ).

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Solution

Surface area of a cone=4070 $c m^{2}$

Diameter of its base=70 cm

$∴ R a d i u s (r) = \frac{70}{2} = 35 c m ∴ I t s s l a n t h e i g h t = \frac{S u r f a c e a r e a}{π r} = \frac{4070 \times 7}{22 \times 35} = 37 c m$

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Diameter of the base of a cone is 10.5 cm and its slant height is 10 cm. Find its curved surface area.

Diameter of the base of a cone is $10.5 c m$ and its slant height is $10 c m$ . Find its curved surface area. $[A s s u m e π = \frac{22}{7}]$

4 : 7

792 {c m}^{2}

π = \frac{22}{7}

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