Curved surface area of a frustum cone = π(r + R)s ⇒ 2.34 cm2
Total surface area of a frustum of cone =π (r + R)s + πr2 + πR2⇒ 25.8cm2
Larger circle area = πR2 ⇒ 12.5 cm2
Smaller circle area = πr2 ⇒ ?
Therefore,
SA = π(r + R)s + πr2 + πR2
25.8 = 2.34 +Area of smaller circle + 12.5
25.8−2.34−12.5=Area of smaller circle
Area of smaller circle of a frustum cone = 10.96 cm2