Question

The curved surface area of a right circular cylinder of height $14cm$ is $88c{m}^2$. Find the diameter of the base of the cylinder.

Answer 1

Given:

The curved surface area of a right circular cylinder, $\text{(C.S.A)}=88c{m}^2$

Height of the cylinder $\left(h\right)=14cm$

Let, Radius of the cylinder be "$r$".

Since, Curved surface area of a right circular cylinder $=2\pi rh$ sq.units

$\Rightarrow 2\pi rh=88c{m}^2$

$\Rightarrow 2\times \frac{22}{7}\times r\times h=88c{m}^2$

$\Rightarrow \frac{44}{7}\times r\times 14cm=88c{m}^2$

$\Rightarrow r=\frac{7}{44}\times \frac{1}{14cm}\times 88c{m}^2$

$\Rightarrow r=\frac{1}{1}\times \frac{1}{2}\times 2cm$

$\Rightarrow r=1cm$

$\Rightarrow$ Diameter of the radius is $2\times r=2\times 1cm=2cm$

Hence, Diameter of the radius is $2cm$.