The curved surface area of a right circular cylinder whose radius is $a$ units and height is $b$ units, is equal to

π a^{2} b

sq.cm

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2 π a b

sq.cm

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2 π

sq.cm

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2

sq.cm

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Solution

The correct option is B $2 π a b$ sq.cm
We have,
$r = a u n i t s, h = b u n i t s$

We know that the curved surface area
$= 2 π r h$

So,
$= 2 π a b s q . u n i t s$

Hence, this is the answer.

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