CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The curved surface area of frustum cone is 1,200 cm. The diameter of a cone is 50 and 12 cm. Find the slant height. (Use π = 3).


A
12.22 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
11.22 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
14.22 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
12.90 cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 12.90 cm

Curved surface area = π(R + r)s

Diameter = radius ×2

Radius, R = 25 cm, r = 6 cm

1,200 = 3×(25+6)×s

1,200 = 3×(31)×s

1,200/93 = s

Slant Height = 12.90 cm


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Shape Conversion of Solids
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon