The curved surface area of frustum cone is 612 $m m^{2}$ . The diameter of a top cone is 10 and the radius of the bottom cone is 4 mm. Find the slant height. (Use $π$ = 3).

17.5 mm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

22.66 mm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

19.5 mm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10.5 mm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 22.66 mm
Curved surface area = $π$ (R + r)s
Diameter = radius $\times 2$
Radius, R = 5 mm, r = 4 mm
612 = $3 \times (5 + 4) \times s$
612 = $3 \times (9) \times s$
$612 / 3 \times 9$ = s
Slant Height = 22.66 mm

Suggest Corrections

Similar questions

Q. The slant height of a cone is 25 mm, top and bottom diameter is 0.2 and 0.4 mm respectively. Find the curved surface area of a frustum of cone. (Use

π

= 3.14)

The curved surface area of frustum cone is 360 $i n^{2}$ . The diameter of a top cone is 12 and the bottom cone is 20 in. Find the slant height. (Use $π$ = 3.14). Round off your answer to the nearest whole number.

Q. The surface area of a frustum cone is 3,300 mm

^{2}

. The larger and smaller radius of the cone is 5 and 2 mm. find its slant height. (Use

π

= 22/7)

Q. Find the curved surface area of a frustum of a cone. The slant height is

15 cm

, top and bottom diameter is

4 cm

and

10 cm

respectively. (Use

π = 3

)

Q. The total surface area of frustum cone is 2,700

m^{2}

. The diameter of a top cone is 3 and the bottom cone is 4 m. What is the curved surface area of a frustum cone? (Use

π

= 3).

Join BYJU'S Learning Program

The curved surface area of frustum cone is 612 mm2. The diameter of a top cone is 10 and the radius of the bottom cone is 4 mm. Find the slant height. (Use π = 3).

The correct option is B 22.66 mmCurved surface area = π(R + r)sDiameter = radius ×2Radius, R = 5 mm, r = 4 mm612 = 3×(5+4)×s612 = 3×(9)×s612/3×9 = sSlant Height = 22.66 mm

The curved surface area of frustum cone is 612 $m m^{2}$ . The diameter of a top cone is 10 and the radius of the bottom cone is 4 mm. Find the slant height. (Use $π$ = 3).

The correct option is B 22.66 mm
Curved surface area = $π$ (R + r)s
Diameter = radius $\times 2$
Radius, R = 5 mm, r = 4 mm
612 = $3 \times (5 + 4) \times s$
612 = $3 \times (9) \times s$
$612 / 3 \times 9$ = s
Slant Height = 22.66 mm