The curves x2-y2-16 and y2-6 x intersects at

The correct option is B (2, 2√3) ...

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Angle of Intersection of Two Curves

The curves x2...

Question

The curves x²+y²=16 and y²=6x intersects at

(2, 2√3)

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(0, 2)

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(2, 0)

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(0, 2√3)

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Similar questions

x^{2} - 6 x + y^{2} + 8 = 0

x^{2} - 8 y + y^{2} + 16 - k = 0, (k > 0)

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y^{2} = 6 x, 9 x^{2} + b y^{2} = 16

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Prove that the curves $y^{2} = 4 x a n d x^{2} + y^{2} - 6 x + 1 = 0$ touch each other at the point (1, 2).

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