Question

The D.E whose solution is $y=C^2+\frac{C}{x}$ is:

• A. $y=x^4{y}_1-xy{{}_1}^2$
• B. $y=x^{4}y{{}_1}^2-x^2{y}_1$
• C. $y=x^{4}y{{}_1}^2-x{y}_1$
• D. $y=x^{4}y{{}_1}^2+x{y}_1$

Answer 1

The correct option is C $y=x^{4}y{{}_1}^2-x{y}_1$

$y=C^2+c/x$
$\Rightarrow y_1=-C/x^2$
$C=-y_1{x}^2$
$y=y_1^2{x}^4-y_{1}x$