The daily sale of kerosene ( in liters ) in a ration shop for six days is as follows:
$75, 120, 12, 50, 70.5$ and $140.5$
The average daily sale is

150

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10

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142

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78

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Solution

The correct option is D $78$
By definition of average $= \frac{75 + 120 + 12 + 50 + 70.5 + 140.5}{6} = 78$
However, without calculating we can say that the answer is $D$ since the average lies between the maximum and the minimum.

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The daily sale of kerosene ( in liters ) in a ration shop for six days is as follows:75,120,12,50,70.5 and 140.5 The average daily sale is

The correct option is D 78By definition of average =75+120+12+50+70.5+140.56=78However, without calculating we can say that the answer is D since the average lies between the maximum and the minimum.

The daily sale of kerosene ( in liters ) in a ration shop for six days is as follows:
$75, 120, 12, 50, 70.5$ and $140.5$
The average daily sale is

The correct option is D $78$
By definition of average $= \frac{75 + 120 + 12 + 50 + 70.5 + 140.5}{6} = 78$
However, without calculating we can say that the answer is $D$ since the average lies between the maximum and the minimum.