The daily sale of kerosene (in litres) in a ration shop for six days is as follows : $75$ , $120$ , $12$ , $50$ , $70.5$ and $140.5$ The average daily sale is

150

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10

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142

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78

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Solution

The correct option is D $78$
Mean $= \frac{75 + 120 + 12 + 50 + 70.5 + 140.5}{6} = 78$
The average daily sale is therefore the mean $= 78.$

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The daily sale of kerosene (in litres) in a ration shop for six days is as follows : 75, 120, 12, 50, 70.5 and 140.5 The average daily sale is

The correct option is D 78Mean=75+120+12+50+70.5+140.56=78The average daily sale is therefore the mean=78.

The daily sale of kerosene (in litres) in a ration shop for six days is as follows : $75$ , $120$ , $12$ , $50$ , $70.5$ and $140.5$ The average daily sale is

The correct option is D $78$
Mean $= \frac{75 + 120 + 12 + 50 + 70.5 + 140.5}{6} = 78$
The average daily sale is therefore the mean $= 78.$