Question

The damage and repair log of an electronic transistor are given below.
Damaged: 9%
Repaired: 5/2%
Damaged: 7%
Repaired: 13/2%

Calculate the final status of functonality of the transistor?

• A. 92%
• B. 89.5%
• C. 93%
• D. 95.5%

Answer 1

The correct option is C 93%

On subtracting the damaged parts and adding the repaired ones to calculate the working status, we have,


100 + (-9) + $\frac{5}{2}$ + (-7) + ($\frac{13}{2}$)
[by commutative property ]

= (100 - 9 -7) + ($\frac{5}{2}$+ $\frac{13}{2}$ )
[by associative property]

= 84 + $\frac{18}{2}$

= 84 + 9

= 93%

Hence, the final status of functionality of the transistor is 94%.