Question

The dark blue colour of the solution formed when excess of ammonia is added to a solution of copper (II) sulphate is due to the presence of the ion :

• A. $\left[Cu\right(OH{)}_4(H_{2}O{)}_2{]}^{2+}$
• B. $\left[Cu\right(H_{2}O{)}_6{]}^{2+}$
• C. $\left[Cu\right(N{H}_4{)}_2(H_{2}O{)}_4{]}^{4+}$
• D. $\left[Cu\right(N{H}_3{)}_4(H_{2}O{)}_2{]}^{2+}$
• E. $\left[Cu\right(N{H}_3{)}_2(H_{2}O{)}_4{]}^{2+}$

Answer 1

The correct option is E $\left[Cu\right(N{H}_3{)}_2(H_{2}O{)}_4{]}^{2+}$

When excess of ammonia is added to a solution of Copper (II) sulphate , tetraamminediaquacopper (II) is formed due to which the solution is deep blue in colour.

$\therefore$ Answer is $\left[Cu\right(N{H}_3{)}_4(H_{2}O{)}_2{]}^{2+}$