The data for an agricultural field for a specific month are given below:
Pan Evaporation = 100 mm
Effective Rainfall = 20 mm (after deducting losses due to runoff and deep percolation)
Crop Coefficient = 0.4
Irrigation Efficiency = 0.5
The amount of irrigation water (in mm) to be applied to the field in that month, is

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Solution

The correct option is B 40
$C_{u} = K \times$ pan evaporation
$C_{u} = 0.4 \times 100 =$ 40 mm
CIR = 40 - 20 = 20 mm
FIR $= \frac{20}{0.5} =$ 40 mm
hence option B correct.

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The correct option is B 40Cu=K× pan evaporation Cu=0.4×100= 40 mm CIR = 40 - 20 = 20 mm FIR =200.5= 40 mm hence option B correct.

The correct option is B 40
$C_{u} = K \times$ pan evaporation
$C_{u} = 0.4 \times 100 =$ 40 mm
CIR = 40 - 20 = 20 mm
FIR $= \frac{20}{0.5} =$ 40 mm
hence option B correct.