Question

The data shows the length of various baby reptiles (in ft):


The difference between the longest and the shortest reptile is .

• A. $\frac{2}{6}ft$
• B. $\frac{4}{6}ft$
• C. $\frac{5}{6}ft$
• D. $\frac{3}{6}ft$

Answer 1

The correct option is D $\frac{3}{6}ft$

Let's convert all the fractions in the given table into equivalent fraction with denominator 6.

$\frac{2}{3}$ $\text{=}\frac{2}{3}\times \frac{2}{2}\text{=}\frac{4}{6}$

$\frac{1}{2}$ $\text{=}\frac{1}{2}\times \frac{3}{3}\text{=}\frac{3}{6}$

The new table will be:


When the denominators are the same, the fraction with the lesser numerator is the lesser fraction and the fraction with the greater numerator is the greater fraction.

$\text{From the table, we can say that,}$
$\text{Length of the longest baby reptile =}\frac{4}{6}\text{ft}$

$\text{Length of the shortest baby reptile =}\frac{1}{6}\text{ft}$

$\text{Now, let's find the difference between the}$ $\text{longest and the shortest reptile:}$

$⟹\frac{4}{6}\text{-}\frac{1}{6}\text{=}\frac{4-1}{6}\text{=}\frac{3}{6}$


$\therefore \text{The difference between the longest}$ $\text{and the shortest reptile is}\frac{3}{6}\text{ft.}$