The correct option is A 99 is an outlier because it is numerically distant from the remaining data set.
The list of the values in the data set: 21, 23, 30, 31, 40, 48, 49, and 99.
The minimum value is 21, and the maximum value is 99. So, the spread is from 21 to 99. Hence, option A is incorrect.
In the given data set, there are 8 values. So, the center is average of 4th and 5th value, which is 31+402 = 35.5
31 is not the middle point value or center. Hence, option B is incorrect.
Since 99 is numerically distant from the remaining data set, it is an outlier. Hence, option C is correct.
Since 49 is closer to the other values, it is not an outlier. Hence, option D is incorrect.