Question

The daughter nucleus formed when ${}^{18}F$ undergoes position emission is?

• A. ${}^{14}N$
• B. ${}^{16}O$
• C. ${}^{18}O$
• D. ${}^{19}F$
• E. ${}^{20}Ne$

Answer 1

The correct option is C ${}^{18}O$

Positron emission is a kind of Beta decay. So the resulting nucleus will have the same mass number as $F$ that is $18$, but its atomic number or the number of protons will be reduced by $1$. $F$ has an atomic number of $9$, hence the resulting nucleus will have an atomic number of $8$. Thus, the resulting nucleus will be Oxygen, since it has an atomic number of $8$. Thus, ${}^{18}O$ is formed.

Option C is the correct answer.