The correct option is
C Carriers
Haemophilia is a X-linked recessive disorder. Since, males are hemizygous for chromosome, one copy of the affected gene in each cell is sufficient to cause the disorder (X
hY). Females have two X chromosomes and hence need two copies of the affected gene to cause the disorder (X
hX
h). Females heterozygous (X
hX) for this trait be normal but serve as a carrier of the disease. According to the question, man has haemophilia (X
hY) and woman is normal (XX).
Parent generation : XX x X
hY
Gametes : XX --> XhY
| X
| X |
Xh
| XhX carrier girl | XhX carrier girl
|
Y | XY normal boy
| XY normal boy
|
F
1 generation = 1 normal carrier girl : 1 normal boy
Thus, the correct answer is option B.