Question

The de-Brogile wavelength of an electron moving in a circular orbit is $\lambda$. The minimum radius of orbit is

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

We know $2\pi r=n\lambda$

From minimum radius $n=1$

$2\pi r_{min}=\lambda$

$r_{min}=\frac{\lambda }{2\pi }$