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Question

The de-Brogile wavelength of an electron moving with a velocity 1.5×108 ms1 is equal to that of a photon. The ratio of the kinetic energy of the electron to that of the energy of photon is (apply non-relativistic for electron)

A
2
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B
4
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C
12
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D
14
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Solution

The correct option is D 14
Given, v=1.5×108 ms1

The energy of a photon is,

E=hcλ ........(1)

The de-Broglie wavelength of the electron is,

λ=hp=hmv

p=hλ

KE=12mv2=12pv=hv2λ ........(2)

From (1) and (2) we get,

KEE=hv2λhcλ=v2c

=1.5×1086×108=14

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (D) is the correct answer.

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