Question

The de Brogile wavelength of the electron in the ground state of the hydrogen atom is (Radius of the first orbit of hydrogen atom = $0.53\stackrel{\circ }{A}$

• A. $1.67\stackrel{\circ }{A}$
• B. $3.33\stackrel{\circ }{A}$
• C. $106\stackrel{\circ }{A}$
• D. $0.53\stackrel{\circ }{A}$

Answer 1

The correct option is B $3.33\stackrel{\circ }{A}$

$2\pi r=n\lambda \Rightarrow 2\pi r=1\times \lambda \Rightarrow \lambda =2\pi r=2\times 3.14\times 0.53=3.33\stackrel{\circ }{A}$