The de-Broglie wavelength associated with a hydrogen atom moving with a thermal velocity of 3 km/s will be

1 \circ A

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0.66 \circ A

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6.6 \circ A

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66 \circ A

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Solution

The correct option is B $0.66 \circ A$
By using $λ = \frac{h}{m v_{r m s}} \Rightarrow λ = \frac{6.6 \times 10^{- 34}}{2 \times 1.67 \times 10^{- 27} \times 3 \times 10^{3}} = 0.66 \circ A$

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