Question

The de-Broglie wavelength associated with an electron accelearated to potential difference of V volt is:

• A. $V\times {10}^{-10}m$
• B. $\sqrt{\frac{150}{V}}{A}^0$
• C. $\frac{150}{V}{A}^0$
• D. $150V\times {10}^{-8}m$

Answer 1

Answer: (B)

$\sqrt{\frac{150}{V}}{A}^0$

$\frac{1}{2}m{v}^2=eV$

$p=\sqrt{2meV}$

$\lambda =\frac{h}{p}$

$=\frac{h}{\sqrt{2meV}}$

$=\sqrt{\frac{150}{V}}{A}^o$

So, the answer is option (B).