wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The de-Broglie wavelength of a free electron with kinetic energy E is λ. If the kinetic energy of the electron is doubled, the de-Broglie wavelength is:

A
λ2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2λ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
λ2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2λ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A λ2
Kinetic energy initially is given by:
E=12mv2=p22m
p=2mE
where
m: Mass of the particle
v: Speed of the particle
p: Momentum of the particle

De-broglie wavelength is given by,
λ=hp
λ=h2mE

Given E2=2E1
λ2=λ12
Given λ1=λ,λ2=λ2

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
De Broglie's Explanation
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon