CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The de-Broglie wavelength of a neutron at $${ 27 }^{ o }C$$ is $$\lambda $$. What will be its wavelength at $${ 927 }^{ o }C$$?


A
λ/2
loader
B
λ/3
loader
C
λ/4
loader
D
λ/9
loader

Solution

The correct option is A $$\lambda /2$$
$$\quad { \lambda  }_{ neutron }\propto \cfrac { 1 }{ \sqrt { T }  } \Rightarrow \cfrac { { \lambda  }_{ 1 } }{ { \lambda  }_{ 2 } } =\sqrt { \cfrac { { T }_{ 2 } }{ { T }_{ 1 } }  } $$

$$\Rightarrow \cfrac { { \lambda  }_{ 1 } }{ { \lambda  }_{ 2 } } =\sqrt { \cfrac { (273+927) }{ (273+27) }  } =2\Rightarrow { \lambda  }_{ 2 }=\cfrac { \lambda  }{ 2 } $$

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image