The de-Broglie wavelength of a particle accelerated with $150 v o l t$ potential is $10^{- 10} m$ . If it accelerated by $600 v o l t s$ p.d. its wavelength will be

0.25 A^{o}

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0. 5 A^{o}

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1.5 A^{o}

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2 A^{o}

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Solution

The correct option is B $0.25 A^{o}$
Given,

$λ = \frac{h c}{e V} w h e r e, V = p o t e n t i a l$

$λ α \frac{1}{V}$

$10^{- 10} α \frac{1}{150} . . . . . . (1)$

$λ α \frac{1}{600} . . . . . . (2)$

Divide (2) by (1)

$\frac{λ}{10^{- 10}} = \frac{150}{600} = \frac{1}{4}$

$\Rightarrow λ = 0.25 \times 10^{- 10} m = 0.25 A^{o}$

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The de-Broglie wavelength of a particle accelerated with 150 volt potential is 10−10 m. If it accelerated by 600 volts p.d. its wavelength will be

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