The de-Broglie wavelength of a particle with mass 1gm and velocity 100m/sec is
6.63 × 10-33 m
6.63 × 10-34 m
6.63 × 10-35 m
6.65 × 10-35 m
From De - Broglie wavelenght, we know
λ = hp ⇒ λ = hmv
Here m = 1gm
v= 100 m/s
⇒ λ = 6.63×10−3410−3×100=6.63×10−33m
The de Broglie wavelength of a particle with mass 1 gram and velocity 100 m/sec is
The de-Broglie wavelength associated with a particle of mass 10−6 kg moving with a velocity of 10 ms−1, is