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Question

The de-Broglie wavelength of a particle with mass 1gm and velocity 100m/sec is


A

6.63 × 10-33 m

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B

6.63 × 10-34 m

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C

6.63 × 10-35 m

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D

6.65 × 10-35 m

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Solution

The correct option is A

6.63 × 10-33 m


From De - Broglie wavelenght, we know

λ = hp λ = hmv

Here m = 1gm

v= 100 m/s

λ = 6.63×1034103×100=6.63×1033m


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