Question

The de Broglie wavelength of a tennis ball of mass 60 g moving with a velocity of $\text{10}m/s$ is approxiamately: $\text{(plancks's constant,}h=6.63\times {10}^{-34}Js)$

• A. ${10}^{-31}m$
• B. ${10}^{-16}m$
• C. ${10}^{-25}m$
• D. ${10}^{-33}m$

Answer 1

The correct option is D ${10}^{-33}m$

According to de-Broglie hypothesis,
$\lambda =\frac{h}{mv}$
where
$h=\text{Planck’s constant}m=\text{mass of particle}v=\text{velocity of particle}$

Given :
$h=6.63\times {10}^{-34}Jsm=60g=60\times {10}^{-3}kgv=10m/sec$

Substituting the values,
$\lambda =\frac{6.63\times {10}^{-34}}{60\times {10}^{-3}\times 10}=1.1\times {10}^{-33}m$