Question

The de-Broglie wavelength of a tennis ball of mass $60g$ moving with a velocity of $10meterpersecond$ is approximately: (take, planck’s constant, $h=6.63\times {10}^{-34}Js$ )

• A. ${10}^{-31}$ meters
  
  
• B. ${10}^{-25}$ meters
• C. ${10}^{-16}$ meters
• D. ${10}^{-33}$ meters

Answer 1

The correct option is D ${10}^{-33}$ meters

According to de-Broglie hypothesis, all matter has both particle and wave nature.
De Broglie wavelength defined the wave nature of a particle as $\lambda =\frac{h}{p}$ OR = $\frac{h}{mv}$
Where, $h=6.63\times {10}^{-34}Js$ = $6.63\times {10}^{-34}kg{m}^2{s}^{-1}$
$v=10m{s}^{-1}$
$m=60g=0.060kg$
λ = wavelength associated with the ball
Using: $\lambda =\frac{h}{mv}=6.63\times 10-34kg{m}^2{s}^{-1}/(0.060kg\times 10m{s}^{-1}$
= ${10}^{-33}m$ (approximately)